nKOH=0.07 , nH+(hcl) = nCl-(hcl)=0.025c1 ,nH+(h2so4)= 0.05C2 , nSO4 2- =0.025c2
. tổng nH+ = 0.025 c1 + 0.05 c2
OH- + H+ -----> H2O
0.07 ----> 0.07
---> 0.025C1 + 0.05C2 = 0.07 (1)
m muối = mK+ + mCl- + mSO4 2- = 0.07x39 + 35.5x0.025C1 + 96x 0.025C2 = 5.715
---> 0.8875C1 + 2.4C2...