Kết quả tìm kiếm

b. A^{3}=\left (\sqrt[3]{6\sqrt{3}+10}-\sqrt[3]{6\sqrt{3}-10} \right )^{3} = 6\sqrt{3}+10 -3.\sqrt[3]{6\sqrt{3}+10}\sqrt[3]{6\sqrt{3}-10}\left ( \sqrt[3]{6\sqrt{3}+10}-\sqrt[3]{6\sqrt{3}-10} \right )-\left (6\sqrt{3}-10 \right ) =20-3\sqrt[3]{108-100}.A \Rightarrow A^{3}+6A-20=0 \Leftrightarrow...

a)\sqrt[3]{48}-\sqrt[3]{184}+\sqrt[3]{162}=\sqrt[3]{2^{3}.6}-\sqrt[3]{2^{3}.23}+ \sqrt[3]{3^{3}.6}=2\sqrt[3]{6}-2\sqrt[3]{23}+3\sqrt[3]{6}=5\sqrt[3]{6}-2\sqrt[3]{23}