Toán 9 [Lớp 9] Rút gọn

Mộc Nhãn said:

1.[tex]Q=(\frac{\sqrt{a}}{\sqrt{a}+1}-\frac{1}{a-\sqrt{a}}) : (\frac{1}{\sqrt{a}+1}+\frac{2}{a-1})=\frac{\sqrt{a}.\sqrt{a}(\sqrt{a}-1)-(\sqrt{a}+1)}{\sqrt{a}(\sqrt{a}-1)(\sqrt{a}+1)}:\frac{\sqrt{a}-1+2}{(\sqrt{a}-1)(\sqrt{a}+1)}=\frac{a\sqrt{a}-a-\sqrt{a}-1}{\sqrt{a}(\sqrt{a}-1)(\sqrt{a}+1)}:\frac{\sqrt{a}+1}{(\sqrt{a}-1)(\sqrt{a}+1)}=\frac{a\sqrt{a}-a-\sqrt{a}-1}{\sqrt{a}(\sqrt{a}+1)}[/tex]
2. [tex]P=(\frac{2\sqrt{x}}{\sqrt{x}+3}+\frac{\sqrt{x}}{\sqrt{x}-3}-\frac{3x+3}{x-9}):\frac{2\sqrt{x}-2}{\sqrt{x}+3}=\frac{2\sqrt{x}(\sqrt{x}-3)+\sqrt{x}(\sqrt{x}+3)-3x-3}{(\sqrt{x}-3)(\sqrt{x}+3)}:\frac{2\sqrt{x}-2}{\sqrt{x}+3}=\frac{-3\sqrt{x}-3}{(\sqrt{x}-3)(\sqrt{x}+3)}:\frac{2\sqrt{x}-2}{\sqrt{x}+3}=\frac{-3(\sqrt{x}+1)}{2(\sqrt{x}-1)(\sqrt{x}-3)}[/tex]

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