Tìm x : 2^(x-1) - 2^(x^2-x) = (x-1)^2

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nguyenbahiep1

[laTEX]2^{x-1} - 2^{x^2-x} = x^2-x - (x-1) \\ \\ 2^{x-1} + (x-1) = 2^{x^2-x} + x^2-x \\ \\ f(t) = 2^t + t \Rightarrow f'(t) = 2^t.ln2 + 1 > 0 \Rightarrow f(x) -dong-bien \\ \\ f(x-1) = f(x^2-x) \Rightarrow x-1 = x^2-x \Rightarrow x = 1 [/laTEX]
 
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