Ai giỏi Hóa giúp mk vs????

T

thupham22011998

Đặt $n K=n A=x mol$

$2K+2HCl->2KCl+H_2$
x.................................x/2 mol

$2A+2HCl->2ACl+H_2$
x.................................x/2 mol

Ta có: $n H_2=x/2+x/2=6,72/22,4=0,3$

$-->x=0,3 mol$

Lại có:$ mhh=18,6g$

$--> m K+ m A=18,6g$

$-->0,3 . 39+ 0,3A=18,6$

$-->A=23$

Vậy A là $Na$
 
I

ilikeenglish

(Hóa 10)

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