a)[tex]\frac{5a^2-10ab+5b^2}{2a^2-2ab+b^2}:x=\frac{8a-8b}{10a^3+10b^3}\\ \Leftrightarrow \frac{5(a-b)^2}{2(a^2-ab+b^2)}:x=\frac{8(a-b)}{10(a+b)(a^2-ab+b^2)}\\ \Leftrightarrow \frac{5(a-b)^2}{2(a^2-ab+b^2)}:x=\frac{4(a-b)}{5(a+b)(a^2-ab+b^2)}\\ \Leftrightarrow x=\frac{5(a-b)^2}{2(a^2-ab+b^2)}:\frac{4(a-b)}{5(a+b)(a^2-ab+b^2)}\\ \Leftrightarrow x=\frac{5(a-b)^2}{2(a^2-ab+b^2)}.\frac{5(a+b)(a^2-ab+b^2)}{4(a-b)}=\frac{25(a-b)(a+b)}{8}[/tex] b) Làm tương tự
[tex]\frac{5a^{2}-10ab+5b^{2}}{2a^{2}-2ab+2b^{2}}:x=\frac{8a-8b}{10a^{3}+10b^{3}} \frac{5a^{2}-10ab+5b^{2}}{2a^{2}-2ab+2b^{2}}:\frac{8a-8b}{10a^{3}+10b^{3}}=x \frac{5(a^{2}-2ab+b^{2})}{2(a^{2}-ab+b^{2})}:\frac{8(a-b)}{10(a^{3}+b^{3})}=x \frac{25(a^{2}-2ab+b^{2})(a^{3}+b^{3})}{8(a^{2}-ab+b^{2})(a-b)}=x \frac{25(a-b)^{2}(a+b)(a^{2}-ab-b^{2})}{8(a^{2}-ab+b^{2})(a-b)}=....[/tex]