Tiếp tục nha!
$8a^2+a-72=8(a^2+\frac{1}{8}a-9)$
$=8\left ( a^2+2.a.\frac{1}{16}+\frac{1}{256}-\frac{2305}{256} \right )$
$=8(a+\frac{1}{16})^2-\frac{2305}{32}$
$= \left [ \sqrt{8}\left ( a+\frac{1}{16} \right )+\sqrt{\frac{2305}{32}} \right ] \left [ \sqrt{8}\left ( a+\frac{1}{16} \right...